trapezium ABCD in which AB||CD,AB=8cm,BC=6cm,CD=4cm and angleB=60°
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Answer:
1. Draw AB = 8 cm.
2. At B draw an angle of 60.
3. With centre B draw an arc of 6 cm.
4. On AB, mark a point E such that BE = difference of AB and CD i.e. 8 – 4 = 4 cm.
5. Join CE.
6. With centre C, draw an arc of 4 cm and with centre A draw an arc of CE = AD. These arcs intersect at point D.
7. Join AD and CD.
Hence, ABCD is the required trapezium.
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