Question

Treatment of cyclopentanone =O with methyl lithium
gives which of the following species? [2015]
(a) Cyclopentanonyl cation
(b) Cyclopentanonyl radical
(c) Cyclopentanonyl biradical
(d) Cyclopentanonyl anion

Answer 1

Treatment of cyclopentanone =O with methyl lithium

gives which of the following species? [2015]

(a) Cyclopentanonyl cation

(b) Cyclopentanonyl radical

(c) Cyclopentanonyl biradical

(d) Cyclopentanonyl anion

Answer 2

Treatment of cyclopentanone =O with methyl lithium gives Cyclopentanonyl anion.

Option: (d)

Explanation:

• Cyclopentanone has the formula of (CH2)4CO whereas, Methyl lithium has formula CH3Li .These are the two reactants.

• When these 2 react there's an hydrogen ion which is present  on cyclopentanone comes into action.

• It will also form an intermediate product

• The methyl lithium will take the active proton from the cyclopentanone. It will then form lithium in place of the alpha hydrogen.

• The reaction will also form methane as side product.

• Hence the final product will be Lithium Cyclopentanonyl anion.

To know more about Cyclopentanonyl radical,

convert the following temperature to celsius scale 500k 336k ..

https://brainly.in/question/9075836