Question

Triangle ABC, AB=AC, and a bisector angle B and angle C intersect at O ,if M is a point BO produces proved that ABC=MOC

Answer 1

"In ABC triangle, by angle sum property we get

x + 2 + ∠A = 180°

⇒ x + y + (∠A) = 90°

⇒ x + y = 180° – (∠A) à

In ΔBOC, we have

x + y + ∠MOC = 180°

180° – (∠A/2) + ∠MOC = 180° [From (1)]

∠MOC = 180° – 180° + (∠A)

∠MOC = 0° + (∠A)

"

Answer 2

x + 2 + ∠A = 180°

⇒ x + y + (∠A) = 90°

⇒ x + y = 180° – (∠A) à

In ΔBOC, we have

x + y + ∠MOC = 180°

180° – (∠A/2) + ∠MOC = 180° [From (1)]

∠MOC = 180° – 180° + (∠A)

∠MOC = 0° + (∠A)

"