Triangle ABC corresponding triangle PQR, If AB : PQ = 4:5, find A (triangle ABC) : A (triangle PQR)
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Answer:
Let AD be the perpendicular dropped from A to the side BC and PS be the perpendicular dropped from P to the side QR respectively.
Since, ΔABC∼ΔPQR, we have ΔABD∼ΔPQS.
Therefore,
PQ
AB
=
PS
AD
=
QR
BC
⇒
arΔPQR
arΔABC
=
PS×QR
AD×BC
=
PQ
AB
×
PQ
AB
=
PQ
2
AB
2
=
9
1
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