triangle ABC if angle b is equal to 60 degree and Angle C is equal to 80 degree and bisector of angle abc and angle ACB meet at a point then find the measure of angle BOC
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angle b=60
so angle obc=30
angle c=80
so angle ocb =40
in triangle ocb
angle ocb+angle obc +angle boc =180
30+40 +angle boc=180
angle boc. =180-70
angle boc =110
so angle obc=30
angle c=80
so angle ocb =40
in triangle ocb
angle ocb+angle obc +angle boc =180
30+40 +angle boc=180
angle boc. =180-70
angle boc =110
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Answered by
9
In triangle abc, Angle b=60 aND Angle c=80 So,angle obc=60/2=30 degree(ob is bisector) SIMIlarly angle ocb=40 Now in triangle obc aNGle obc+angle ocb+angle boc=180 30+40+angle boc=180 70+angle boc=180 ANgle boc=180-70 Angle boc=110
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