Question

Triangle abc is a right angled at B. D is a point on side ac such that bd is perpendicular to ac.
prove that angle abd = angle bcd​

Answer 1

Step-by-step explanation:

prove that angle abd = angle bcd

in∆ABD &∆BCD,

BD=BD(common side)

angleABD=angleDBC (90°/2= 45°)

angleADB=angleBDC (BD is perpendicular to AC)

∆DBA iscongurent to ∆DBC (ASA)

angleabd = anglebcd (CPCTE)

Hence proved!!