Question

Triangle ABC is acute angled. AD is a altitude from vertex A to BC. Point D is on side BC. AB =6, BC=8, BD = 3. What is the value of AC² ?

Answer 1

Answer:

50

Step-by-step explanation:

AB^2=BD^2+AD^2

6^2=3^2+AD^2

36-9=AD^2

25=AD^2

5=AD

INADC

AD^2+DC^2=AC^2

5^2+(8-3)^2=AC^2

25+25=AC^2

50=AC^2