Question

Triangle ABC is an equilateral triangle with AC =8; find the area of this triangle​

Answer 1

area of = 1/2×b×h

here this is an equilateral triangle so all the side of this triangle will be equal

AB=BC=AC=8cm

there for area of = 1/2×8×8

=1×8×8/2

=16/2

=8

Answer 2

$\huge\sf{Given:-}$

=>ABC is an equilateral triangle

=>AC =8

$\huge\sf{Solution:-}$

As,ABC is an equilateral triangle

therefore,AB=BC=CA=8

Area of equilateral ∆,

=>$\sf \dfrac{√3}{4}×(side)^2$

=>$\sf \dfrac{√3}{4}×(8)^2$

=>$\sf \dfrac{√3}{4}×64$

=>$\sf √3×16$

=>$\sf 1.732×16$

=>$\sf 27.712$

therefore,area of triangle =$\sf 27.712units^2$