Question

Triangle ABC is an isosceles triangle right angled at C. Prove that AB²=2AC²

Answer 1

hypotenuse^2=(one side of triangle^2)+(other side of triangle^2)

AB^2=AC^2+BC^2
AB^2=2AC^2{given AC=BC}

HENCE PROVED

Answer 2

Answer:

Step-by-step explanation:

1.Since it is an isoceles right angled triangle ,hence AB and BC are equal because hypotenuse is the largest side in a right angled triangle and therefore it can't be one of the equal sides.

2.According to Pythagoras theorem

.AB^2=AC^2+BC^2

3.AB^2=AC^2+AC^2

4.AB^2=2AC^2