Question

Triangle ABC is an isosceles triangle with AB= BC. Prove that triangle ABC is congurent to triangle CBA​

Answer 1

Answer:

It is given that two circle having radii 5.5 cm and 4.2 cm touch each other externally. We know, the distance between the centres of the circles touching externally is equal to the sum of their radii. Thus, the distance between their centres is 9.7 cm.

Answer 2

Answer:

In ∆ ABC

GIVEN= AB=BC

TO PROVE = ∆ABC IS CONGRUENT TO ∆ CBA

CONSTRUCTION= AD PERPENDICULAR BC

PROOF= IN ∆ABD AND ∆ADC

= AD= AD ( COMMON)

= AB= BC ( GIVEN)

= ANGLE ADB=ANGLE ADC ( EACH 90 DEGREE)

= SO ( ∆ABD CONGRUENT TO∆ADC) BY SAS

IF ∆ABD CONGRUENT TO ∆ADC THEREFORE ∆ ABC IS CONGRUENT TO ∆ CBA

Step-by-step explanation:

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