Question

triangle ABC is an isosceles triangle with ab equals to 5 cm is equals to 7.5 cm and BC equals to 9 CM. the height of a BC is 6 CM(base-BC). find the area of triangle ABC. now from the vertex see there is of altitude with the base ab find the the measurements of the altitude CE. please it is urgent and important​

Answer 1

Area of triangle ABC = 1/2 *b*h
= 1/2* BC*AD
=1/2*9cm*6cm
=1/2*54
=27cmsq
Therefore area of triangle ABC = 27 cm sq

Length of CE =

Area of triangle = 1/2* b* h

27 cm sq = 1/2* AB*CE

27cm sq = 7.5* CE

1/2*7.5* CE = 27 cm sq

7.5 cm * CE = 27 cm sq /1/2

7.5 cm * CE = 27 cm sq * 2

7.5 cm * CE = 54 cm sq

CE = 54 cm sq /7.5 cm

CE = 7.2 cm

HOPE IT HELPS PLEASE MARK MY ANSWER AS BRAINLIEST