Question

triangle ABC is an obtuse angle triangle and AD perpendicular to BC prove that AC square is equals to a b square + BC square + 2 BC into BD​

Answer 1

AC^2=CD^2+AD^2
=(BC-BD)^2+AD^2
BC^2+BD^2-2BC.BD+AD^2
SO,
=AB^2+BC^2-2BC.BD
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