Question

triangle ABC is an right angle triangle at B. ACDG and BCGF are square. prove that I) triangle BCD = triangle ACG ​

Answer 1

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MarilynEvans

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Answer : -

Given that,

∠ABC = 90°

ACDE and BCFG are squares.

To prove : -

(i) △BCD ≅ △ACG

(ii) AG = BD

Proof : -

(i) In △BCD and △ACG,

BC = CG (same side of the square)

∠ACG = ∠BCD [°.° ∠BCG = ∠ACD = 90° (given) .°. ∠BCG + ∠BCA = ∠ACD + ∠ACB (If equals are added to equals then the sum is equal.)]

AC = CD (same side of the triangle)

.°. △BCD ≅ △ACG

Hence, proved.

(ii) AG = BD (By C.P.C.T)

Hence, proved.

Step-by-step explanation:

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