triangle ABC is an right angle triangle at B. ACDG and BCGF are square. prove that I) triangle BCD = triangle ACG
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Answer : -
Given that,
∠ABC = 90°
ACDE and BCFG are squares.
To prove : -
(i) △BCD ≅ △ACG
(ii) AG = BD
Proof : -
(i) In △BCD and △ACG,
BC = CG (same side of the square)
∠ACG = ∠BCD [°.° ∠BCG = ∠ACD = 90° (given) .°. ∠BCG + ∠BCA = ∠ACD + ∠ACB (If equals are added to equals then the sum is equal.)]
AC = CD (same side of the triangle)
.°. △BCD ≅ △ACG
Hence, proved.
(ii) AG = BD (By C.P.C.T)
Hence, proved.
Step-by-step explanation:
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