Question

triangle ABC is isosceles with ab is equal to AC is equal to 7.5 cm and BC is equal to 9 cm height AD from A to B c is 6 . find the area of a triangle ABC what will be the height from C to AB

Answer 1

Here's your answer friend -:

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Given that -: ∆ABC is isosceles, With



AB = AC = 7.5cm

BC = 9cm

AD = 6


Area(∆ABC) = 1/2 × base × height

. . . = 1/2 × 9 × 6

. . . = 27cm²

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Construct-: CE perpendicular to AB ( height )

Now, we take altitude or height from C to AB as CE

We know that area will always be same but base and height can change.

So, this time we will take AC as base and CE as height.
We also know that area of ∆ABC = 27cm².


area(ABC) = 1/2 × AC × CE

27 = 1/2 × 7.5 × CE

CE = 27 × 2 ÷ 7.5

CE = 7.2cm


Therefore, altitude from C to AB is of 7.2cm.
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Hope it helps.

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Answer 2

Answer:

@vipul3503 your answer is really hardworking keep it up