Question

Triangle abc is right angle at b , ab= 6units and angle c = 60° find ac , bc, and angle a

Answer 1

Answer:

Solution:

Given In ∆ABC, <ABC = 90°

AB = 6 units , BC = 8 units

By Phythogarian theorem:

i) AC² = AB²+BC²

= 6²+8²

= 36+64

= 100

=> AC = √100

=> AC = 10 units.

ii)sinA = BC/AC = 8/10

cosC = BC/AC = 8/10

cosA = AB/AC = 6/10

sinC = AB/AC = 6/10

Now ,

sinAcosC+cosAsinC

= \frac{8}{10}\times\frac{8}{10}+\frac{6}{10}\times\frac{6}{10}

= \frac{64}{100}+\frac{36}{100}

= \frac{64+36}{100}

= $\frac{100}{100}$

= $1$

Therefore,

sinAcosC+cosAsinC =1

••••

Answer 2

Answer:

ANGLE A +ANGLE B+ANGLE C=180

ANGLE A+90+60=180

ANGLE A= 180-150

ANGLE A=30

BC=6 ROOT 3(PROPERTY OF 30-60-90)

AC=2*BC(PROPERTY OF 30-60-90)

AC=12 ROOT 3

Step-by-step explanation: