Question

triangle ABC is right angled at a ad is drawn perpendicular to BC if ab = 5 cm and ac = 10 cm find the area of a triangle ABC also find the length of a AD​

Answer 1

area of triangle = 1/2*base *height

=1/2*AB*AC

= 1/2*5*10

= 50 /2

=25 sq cm

In triangle ABC,

By phy. theorem,

BC^2 = AB^2 + AC^2

BC^2= (5)^2 + (10)^2

BC^2 =25+100

BC^2 = 125

BC=√125

BC= 5√5 cm

1/2*AB*AC= 1/2*BC*AD

25= 1/2* 5√5* AD

AD=25*2/ 5√5

= 5*2/√5

=10 /√5

=(10/√5)*(√5/√5)

=10√5/5

AD=2√5 cm

Answer 2

Step-by-step explanation:

pls mark it as the brainliest answer...

have a bright future ahead...