Question

Triangle ABC is right angled at A. AD is drawn perpendicular to BC. if AB=5cm and AC=12cm,find the area of ABC. Also find the length of AD.

Answer 1

area=1/2×b×h


using Pythagoras theorem base
x²=5²+12²
=144+25
=169
x=13


CB=13cm


height using Pythagoras theorem
x²=12²-6.5²
= 144-42.25
=101.75cm²
x=10.08cm


area=1/2×13×10.08
=13×5.04
=65.52cm²


length of AD=10.08cm