Question

Triangle ABC is right angled at A and AD Is perpendicular to BC. If angle B is of the measure 50° then
find angle BAD and BCA.
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Answer 1

A + B + C = 180°

90° + 50° + C° = 180°

C = 180 - 140

C = 40°

Angle BCA = 40°

In triangle ADC

A + D + C = 180°

A + 90° + 40° = 180°

A= 180° - 130°

A = 50°

ANGLE BAD = 90° - 50°

ANGLE BAD = 40°

Answer 2

Answer:

BAD+ABD+ADB=180...sum of angles of triangle is 180°

BAD+50°+90°=180°

BAD+140°=180°

BAD=180°-140°

BAD=40°

BCA+ABC+BAC=180°

BCA+50°+90°=180°

BCA+140°=180°

BCA=180°-140°

BCA=40°

Step-by-step explanation:

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