Question

Triangle ABC is right angled at b ab =6cm bc =8cm d is the midpoint of ac find bd

Answer 1

Answer:

squaroot of 39

Step-by-step explanation:

take ab to be the bc to be the base so finding midpoint of the hypotenuse we have  1/2 acsquared= ab squared+ bc squared

we get 1/2 ac squared = 6 squared+8 square which gives 100

sqrt{100} = 10 and a half of ten is 5

now we have another right angled triangle with DB as height  DC as base and BC as hypotenuse and using the pythagoras theorem to find BD we have 8 squared minus 5 square which equals 39

find the square root of 39 to get the length of BD

Answer 2

BD=6.2 cm

Step-by-step explanation:

In triangle ABC

Angle B=90 degree

AB=6 cm

BC=8 cm

D is the mid-point of AC.

In triangle ABC

$AC^2=AB^2+BC^2$

Using Pythagoras theorem  

$(hypotenuse)^2=(Base)^2+(perpendicular\;side)^2$

$AC^2=6^2+8^2$

$AC^2=36+64$

$AC^2=100$

$AC=\sqrt{100}=10 cm$

AD=DC=$\frac{1}{2}AC=\frac{1}{2}(10)=5 cm$

We know that when a line is drawn from vertex and divide the opposite side into equal parts then, it will be perpendicular .

In right triangle DBC

$BC^2=DB^2+DC^2$

Substitute the values

$8^2=DB^2+5^2$

$64=DB^2+25$

$DB^2=64-25=39$

$DB=\sqrt{39}=6.2 cm$

#Learns more:

https://brainly.in/question/11548108:Answered by brainly Ms dhoni