Triangle ABC is right angled at B and D is midpoint of BC. Prove that AB²= 4AD²- 3AC²
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I think the question is wrong. It has to be
AC^2 = 4AD^2 - 3AB^2
AC^2 = 4AD^2 - 3AB^2
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Answer:
here is the. answer
PLZ mark it as BRAINLIEST
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