Math, asked by madhusekender, 29 days ago

Triangle ABC is  right angled at vertex A. Calculate the length of BC, if AB = 15 cm and AC = 20 cm.

Select from the Answers below

13 cm 

 

21 cm 

 

25 cm



Answers

Answered by Anonymous
68

Answer:

\huge\mathfrak{\red{Answer}}

\rightarrow\small\bf BC \: = \: 25cm

Step-by-step explanation:

\huge\underline{\overline{\mid{\bold{\blue{\mathcal{Question:-}}\mid}}}}

  • Triangle ABC is  right angled at vertex A. Calculate the length of BC, if AB = 15 cm and AC = 20 cm.

\huge\underline{\overline{\mid{\bold{\blue{\mathcal{Hint:-}}\mid}}}}

  • To find the lenght of BC; we will use the Pythagoras theorem in the ∆ ABC which is right angled at / A .

\huge\underline{\overline{\mid{\bold{\blue{\mathcal{Pythagoras \ theorem:-}}\mid}}}}

  • In a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

\huge\underline{\overline{\mid{\bold{\blue{\mathcal{Required \ Solution:-}}\mid}}}}

Given:-

  • A ∆ ABC where / A = 90°
  • AB = 15 cm
  • AC = 20 cm

To find:-

  • Length of BC.

By Pythagoras theorem we have;

 {H}^{2}  =  {B}^{2}  +  {P}^{2}

 {BC}^{2}  =  {AB}^{2}  +  {AC}^{2}

 {BC}^{2}  =   {15}^{2}  +  {20}^{2}

 {BC}^{2}  = 225 + 400

 BC =  \sqrt{625}

 BC =  \sqrt{ {25}^{2} }

 BC = 25cm

\fbox{\purple{ BC \ = \ 25cm}}

\mathfrak{\red{ \ \ \ \ \ \ \ \ \ \ \ \ @MissTranquil}}

Attachments:
Answered by VAMPlRE
84

\huge \tt Given :

  • In ∆ABC is right angled triangle at vertex A.
  • Length of AB= 15cm and AC = 20 cm.

 \huge \tt Find :

  • Calculate the length of BC.

 \huge \tt Theorem  \: used :

  • In the right angled triangle the square of the hypotenuse side is equal to the sum of squares of other two sides.
  •  \rightarrow\tt    {hypo }^{2}   =  {height}^{2}  +  {base}^{2}

 \huge \tt Solution :

Here vertex is A.

\tt\therefore\: {BC}^{2}  =  {AB}^{2}  + AC

  \tt \rightarrow{BC}^{2}  =  {15}^{2}  +  {20}^{2}

 \tt \rightarrow \:  {BC}^{2}  = 225 + 400

 \rightarrow \tt  \:  {BC}^{2}  = 625

 \tt \rightarrow \:  {BC} =  \sqrt{625}

 \tt \rightarrow \fbox {\tt \green{ BC = 25}}

Length of the BC is 25 cm.

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