Math, asked by rubabislam219, 4 months ago

triangle ABC is right angled triangle at B and D is a point on BC if ad = 18 cm and BD = 9 cm and CD = 4 cm find AC​

Answers

Answered by BrainlyAryabhatta
4

Answer:

Step-by-step explanation:

First thing to do is draw the triangle with the line across it. Having the line creates another right angle triangle which enables us first to calculate AB

AB^2 + BD^2 = AD^2

AB^2 + 9^2 = 18 ^2

AB^2 = 243

By Pythagoras again you can now calculate the length of AC

AC^2 = AB^2 + BC^2

AC^2 = 243 + (9 + 4)^2

AC^2 = 243 + 169

AC = sqrt(412)

AC = 20.28 (2dp)

from above we can know AB=sqrt(18*18-9*9)=9sqrt(3) which sqrt(x)=x^(1/2)

then AC=sqrt(BC*BC+AB*AB)=sqrt(13*13+9*9*3)=sqrt(412) all by using the Pythagorean Theorem.

Answered by Laila17899
0

Answer:

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