Triangle ABC is shown on the graph. What are the coordinates of the image of point B after the triangle is rotated 270° about the origin?
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Without seeing the graph, we don't have the information to give the exact solution. However, I can give you an example to help you figure it out once you determine the original coordinates of B.
There is a formula to calculate a 270° about the origin rotation:
(x, y) → (y, -x)
This means you reverse the order of x and y, and negate the original x-value (flip the sign).
If we rotate the point (3, -5) 270º, it would become (-5, -3) since we reverse 3 and -5, then make 3 negative.
If we rotate the point (-6, -7) 270º, it would become (-7, 6) since we reverse -6 and -7, then make the -6 positive.
There is a formula to calculate a 270° about the origin rotation:
(x, y) → (y, -x)
This means you reverse the order of x and y, and negate the original x-value (flip the sign).
If we rotate the point (3, -5) 270º, it would become (-5, -3) since we reverse 3 and -5, then make 3 negative.
If we rotate the point (-6, -7) 270º, it would become (-7, 6) since we reverse -6 and -7, then make the -6 positive.
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