Question

triangle ABC is similar to triangle pqr are area of triangle ABC equal to 16 cm square and area of area of triangle pqr equal to 81 cm square AB equal to 2 cm find the PQ​

Answer 1

Answer:

PQ = 4.5 cm

Step-by-step explanation:

Given ∆ABC ~∆PQR,

ar(∆ABC) = 16 cm² and

ar(∆PQR)=81 cm²,

AB = 2 cm ,

PQ = ?

/*We know the theorem:

The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.

sides.

=

Therefore,

Answer 2

Step-by-step explanation:

Ar. (△ABC) = 16cm2

Ar. (△PQR) = 81cm2

AB=2cm

For similar triangles the ratio of areas is equal to the ratio of square of its sides.

Thus, A(△PQR)/A(△ABC)=AB²/PQ²

81/16=(2²)/PQ²

PQ²=16×4/81

PQ²= 64/81

PQ= 8/9

PQ=0.8cm