Triangle ABC <-->triangle PQR for the correspondence ABC <--->PQR.2m
arunraimau:
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m<C=100.find m<B. Question is not coming full
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m < P = measure of the angle P = angle P
Given 2 * angle P = 3 * angle Q, and angle C = 100⁰.. To find the measure of angle B
The two triangles ABC and PQR are similar or corresponding.. So
angle A = angle P
angle B = angle Q
angle C = angle R
angle A+ Angle B + angle C = angle P + angle Q + angle R = 180°
angle R = angle C = 100°
angle P + angle Q = 180 - angle C = 80°
angle P + 2/3 * angle P = 80°
=> angle P = 48°
=> angle Q = 32° => angle B = angle Q = 32°
Given 2 * angle P = 3 * angle Q, and angle C = 100⁰.. To find the measure of angle B
The two triangles ABC and PQR are similar or corresponding.. So
angle A = angle P
angle B = angle Q
angle C = angle R
angle A+ Angle B + angle C = angle P + angle Q + angle R = 180°
angle R = angle C = 100°
angle P + angle Q = 180 - angle C = 80°
angle P + 2/3 * angle P = 80°
=> angle P = 48°
=> angle Q = 32° => angle B = angle Q = 32°
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