Question

triangle Abc parallel to triangle Def and their areas are respectively 144cm square and 81 cm square if Ef =27 cm find Bc​

Answer 1

Answer:

$using \: area \: ratio \: theorem \\ \frac{area \: of \: triangle \: abc\: }{area \: of \: triangle \: def} = \frac{ {bc}^{2} }{ {ef}^{2} } \\ \frac{144}{81} = \frac{ {bc}^{2} }{ {27}^{2} } \\ {bc}^{2} = \frac{144 \times 27 \times 27}{81} \\ {bc}^{2} = 144 \times 9 \\ bc = 12 \times 3 = 36 \: cm$