Question

triangle ABC, sag QR is a tangent to the circle with center P
PR =12cm and PQ=6cm.
Find the area of the shaded region

Answer 1

Answer:

26.16cm²

Step-by-step explanation:

Area of the shaded region can caculated as

A = Area of triangle - Area of Segment

Area of triangle = 1/2 × b × h = 1/2 ×12×6 = 36cm²

cos(∠QPR) = 6/12 = 1/2

∠QPR = 60°

Area of segment = πr²∅/360°

                            = π×6²×60/360

                            = 18.84cm²

Therefor, A = 36 - 18.84 = 17.16cm²