triangle ABC sim triangle PQR , such that angle A= angle P LP and angle B= angle Q , PR = 25 cm , AC = 30 cm then ar( Delta ABC) ar( Delta POR) =\ , PQ = 12 cm , AB = 16 cm
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In a △ABC,P and Q are points on sides AB and AC respectively, such that PQ∥BC. If
AP=2.4cm,AQ=2cm,QC=3cm and BC=6cm, find AB and PQIf a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.
Hence
QC
AQ
=
PB
AP
3
2
=
PB
2.4
PB=3.6cm
AB=AP+PB=2.4+3.6=6cm
As PQ∥BC
∠AQP=∠ACB
∠APQ=∠ABC
So by AAA △AQP∼△ACB
Hence
AC
AQ
=
CB
QP
5
2
=
6
QP
QP=2.4cm
So AB=6cm and QP=2.4cm
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