Question

triangle ABC ~triangle DEF and their areas are respectively 49cm^2.and 100cm^2.if DE=17.5cm,then find AB​

Answer 1

Step-by-step explanation:

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Answer 2

$AB=12.25 cm$

Step-by-step explanation:

$\triangle$ABC$\sim\triangle$DEF

Area of triangle ABC=49 square cm

Area of triangle DEF=100 square cm

DE=17.5 cm

When two triangles ABC and DEF are similar  

Then, $\frac{ar(ABC}{ar(DE F)}=(\frac{AB}{DE})^2$

Using the formula  

$\frac{49}{100}=(\frac{AB}{17.5})^2$

$AB^2=\frac{49\times (17.5)^2}{100}$

$AB=\sqrt{\frac{49\times (17.5)^2}{100}}$

$AB=12.25 cm$

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