Math, asked by vaishnavik1309, 3 months ago

triangle ABC - Triangle DEF Area of Triangle ABC is 18 and area of Triangle DEF is 32. if AB = 6 then find DE
(please guys give me quickly answer urgent)​

Answers

Answered by sadiaanam
1

Answer:

The value of DE is 8.

Step-by-step explanation:

As per the data given in the question

We have to calculate the value of DE

As per question

It is given that triangle ABC - Triangle DEF Area of Triangle ABC is 18 and area of Triangle DEF is 32. if AB = 6.

Area of Triangle ABC/Area of Triangle DEF=\frac{(AB)^2}{DE^{2} }

\frac{18}{32}=\frac{6^{2} }{x^{2} }   (let us assume that DE=X)

⇒18x^{2}=1152

x^{2}=\frac{1152}{18}

⇒x=\sqrt{64}

⇒x=8 or DE=8

As per questions triangle ABC - Triangle DEF .

so, the value of DE=8.

Hence, the value of DE is 8.

For such type of questions:

https://brainly.in/question/32422393

#SPJ1

Answered by shikhaprabhakar2203
0

triangle ABC - Triangle DEF Area of Triangle ABC is 18 and area of Triangle DEF is 32. if AB = 6 then find DE is 8.

Step-by-step explanation:

Let the side DE be x.

Area of Δ ABC/ Area of Δ DEF =\frac{AB^{2} }{DE^{2} }

\frac{18}{32} = \frac{6^{2} }{x^{2} }

\frac{18}{32} = \frac{36}{x^{2} }

x^{2} = \frac{32 * 36}{18}

x^{2} = 64

x = \sqrt{64}

x = 8

Hence, the side DE is 8.

Related links

https://brainly.in/question/4208445

#SPJ2

Attachments:
Similar questions