Math, asked by rohitj77035ou9pv9, 1 year ago

triangle ABC~triangle LMN. In triangle ABC, AB =5.5 cm, BC=6cm, CA=4.5 cm. Construct triangle ABC and triangle lmn such that BC upon MN = 5 upon 4

Answers

Answered by amitnrw
41

Answer:

Δ LMN

LM = 4.4 cm

MN = 4.8 cm

NL = 3.6 cm

Step-by-step explanation:

triangle ABC~triangle LMN. In triangle ABC, AB =5.5 cm, BC=6cm, CA=4.5 cm. Construct triangle ABC and triangle lmn such that BC upon MN = 5 upon 4

ΔABC ≅ Δ LMN

AB/LM  = BC / MN  = CA/ NL

BC/MN = 5/4

=> MN = 4BC/5

=> MN = 4 * 6 /5

=> MN = 4.8 cm

AB/LM = 5/4

=> LM = 4AB/5

=> LM = 4 * 5.5 / 5

=> LM = 4.4 cm

CA/ NL = 5/4

=> NL = 4CA/5

=> NL = 4 * 4.5 / 5

=> NL = 3.6 cm

Δ LMN

LM = 4.4 cm

MN = 4.8 cm

NL = 3.6 cm

We can draw triangle using scale & compass

First Draw any one of the line with given length with help of scale.

Then draw two arcs of each length from corner points of line such that arcs intersect at any point,

Join intersecting point with the help of scale to points of first drawn line

Triangle is constructed

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