Triangle ABC- triangle PQR. M is the mid point of BC and N is the point of QR. If the area of triangle ABC=100 sq.cm and the area of triangle PQR = 144 sq.cm. If AM=4 cm then PN is
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Answer:
ar(△ABC)/ar(△PQR) = 100/144
If triangles are similar then ratio of their areas is equal to ratio of square of their corresponding sides
AB^2/PQ^2 = 100/144
AB/PQ = 10/12
AM and PN are medians
Therefore, AM/PN = AB/PQ
4/PN = 10/12
PM = 4.8 cm
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