Triangle abcd angle a is 120 °and angle c is 40 ° find the value of x
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we know that angle of triangle angle A + Angle B + angle c equal to 180 degree angle is equal to 120 degree angle c equal to 40 degree and 120 degree + 40 degree + X equal to 180 degree 160 degree + X equal to 180 degree degree minus 160 degree degree =20 degree
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x will be 20 degree..
by angle sum property=sum of all angles is always equal to 180 degree
so we have to add 120 and 40 = 160 then subtract 160 from 180
by angle sum property=sum of all angles is always equal to 180 degree
so we have to add 120 and 40 = 160 then subtract 160 from 180
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