Question

triangle be 5 cm long, find the length of the other side.
3. The length of two sides of a right triangle are equal. The square of the hypotenuse is
800 cm. Find the length of the each side.
the distance between​

Answer 1

Answer:

20 cm

Step-by-step explanation:

Let the equal sides of the right angle triangle be x

square of the hypotenuse is 800cm

hypotenuse² = 800cm

hypotenuse² = base² + perpendicular²

800cm = x² + x²

800cm = 2x²

x² = 800/2

x² = 400

x = √400

x = 20cm

Hence, the length of other sides is 20cm each.

Answer 2

Answer:

Given :

Ratio of two sides of a parallelogram = 3 : 5

The perimeter of parallelogram = 64 cm

To Find :

The length of sides of the parallelogram

Solution :

Let the ratio constant be "x" . Then sides of paralleogram are 3x and 5x.

Perimeter of parallelogram is given by ,

\begin{gathered} \\ \star \: {\boxed{\purple{\sf{Perimeter_{(parallelogram)} = 2(a + b)}}}} \\ \\ \end{gathered}

⋆

Perimeter

(parallelogram)

=2(a+b)

Here ,

a and b are adjacent sides of parallelogram

We have ,

Perimeter = 64 cm

a = 3x and b = 5x

Substituting the values ;

\begin{gathered} \\ : \implies \sf \: 64\:cm = 2(3x + 5x) \\ \\ \end{gathered}

:⟹64cm=2(3x+5x)

\begin{gathered} \\ : \implies \sf \: 64 \:cm= 2(8x) \\ \\ \end{gathered}

:⟹64cm=2(8x)

\begin{gathered} \\ : \implies \sf \: 64 \:cm= 16x \\ \\ \end{gathered}

:⟹64cm=16x

\begin{gathered} \\ : \implies \sf \: x = \frac{64\:cm}{16} \\ \\ \end{gathered}

:⟹x=

16

64cm

\begin{gathered} \\ : \implies{\underline{\boxed {\red{\mathfrak{x = 4 \: cm}}}}} \\ \\ \end{gathered}

:⟹

x=4cm

Now ,

a = 3x = 3(4) = 12 cm

b = 5x = 5(4) = 20 cm

Hence ,

The Length of sides of parallelogram are 12 cm and 20 cm.