Triangle having vertices (-2,1) (2,-2)
(5,2) is
(a) Equilateral triangle
(b) Right Angle Triangle
(c) Isosceles Right Angle Triangle
(d) none
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Answer:
(d) none
Step-by-step explanation:
To prove with distance formula
Let triangle be ABC
sideAB=√(X2-X1)+(Y2-Y1)
sideAB=√(2+2)+(-2-1)
sideAB=√4-3
sideAB=√7
side BC=√(X2-X1)+(Y2-Y1)
sideBC=√(5-2)+(2+2)
sideBC=√(3+4)
sideBC=√7
sideAC=√(X2-X1)+(Y2-Y1)
sideAC=√(-2-5)+(1-2)
sideAC=√-7-1
sideAC=√8 iota
ABC is an isosceles Triangle but not a Right angled triangle
Since √7 ^2 +√7 ^2≠√8 ^2
Therefore answer is (D) none
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