Question

triangle is isosceles with ab=ac =7.5 cm and bc = 9 cm the height ad from a to BC is 6 cm Find the area triangle ABC What will be the height from C to AB ie CE​

Answer 1

$\underline{\boxed{\bold{Question}}}$

Triangle is isosceles with AB=AC =7.5 cm and Bc = 9 cm the height ad from a to BC is 6 cm Find the area triangle ABC What will be the height from C to AB ie CE

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$\underline{\boxed{\bold{Answer}}}$

$\huge\red{CE=7.2cm}$

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$\huge\mathfrak\blue{Formula}$

$</p><p>Area \: of \: ∆ = \frac{1}{2}×base×height$

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$\underline{\boxed{\bold{Explanation}}}$

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$\huge\green{Given}$

⋆The perpendicular is the height

⋆The perpendicular divides the base into two parts

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${\huge{\underline{\mathcal{\orange{BD=DE=4.5cm}}}}}$

$Then, area \: \frac{1}{2} \times 6×9$

${{\boxed{\mathcal{\pink {Area \: of∆=27cm²}}}}}$

When perpendicular drawn from C

Height =h , base= 7.5

$\frac{1}{2}×h×7.5=27$

${\boxed{\mathcal{\purple {Hence, h=7.2cm}}}}$

[Hope this helps you.../]

Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM

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