Question

triangle is such that AB=3 cm, BC= 2cm, CA=2.5 cm. If AABC ~ ADEF and EF= 4cm, then perimeter of triangle DEF is
(a) 7.5 cm
(b) 15 cm
(c) 22.5 cm
(d) 30 cm​

Answer 1

Step-by-step explanation:

☞︎︎︎ Given : AB= 3cm ,BC=2cm, CA=2.5cm .

and EF = 4cm .

☞︎︎︎Also △ABC∼△DEF

☞︎︎︎ Thus - AB/DE = BC/EF = AC/DF

☞︎︎︎ 3/DE = 2/4 = 2.5/DF

☞︎︎︎ Hence, DE=6cm and DF=5cm

☞︎︎︎ Perimeter of Δ DEF = DE+EF+EF

☞︎︎︎Perimeter of Δ DEF = 4+5+6

☞︎︎︎Perimeter of Δ DEF = 15 cm

Hope it helps you out..