Question

triangle MNO is a right-angled triangle. Its legs are 6 cm and
8 cm long. Length of perpendicular NP on the side MO is
a 4.8cm
b 3.6 cm
c 2.4 cm
d 1.2 cm​

Answer 1

Answer:

a 4.8cm

Step-by-step explanation:

by pythagoras theorem

length of side MO

MO²= MN²+ NO²

MO²= 8²+6²

MO²= 64+36

MO²=100

MO= 10 cm

area of the triangle MNO

(MN×NO)/2

(8×6)/2 =

48/2 =

24cm²

area of the triangle MNO

(NP×MO)/2

24cm² = (NP×10)/2

48 = (NP×10)

48/10 = NP

4.8cm = NP

Answer 2

Answer:

ANS :-   (A) 4.8 cm

Step-by-step explanation:

By Pythagoras theorem

length of side MO

MO²= MN²+ NO²

MO²= 8²+6²

MO²= 64+36

MO²=100

MO= 10 cm

Area of the triangle MNO

(MN×NO)/2

(8×6)/2 =

48/2 =

24cm²

Area of the triangle MNO

(NP×MO)/2

24cm² = (NP×10)/2

48 = (NP×10)

48/10 = NP

4.8cm = NP

Hope this helped you guys .

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