Question

triangle RPQ is a right angled at Q PQ=5cm and RQ=10cm find sin P ×cosP​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Given : Triangle RPQ is right Angled at Q . PQ = 5 cm , RQ = 10 cm

To Find : SinP.CosP

Solution:

Triangle RPQ is right Angled at Q

PQ = 5 cm

RQ = 10 cm

PR² = PQ² + RQ²

=> PR² = 5² + 10²

=> PR² = 125

=> PR = 5√5  cm

Sin P  = PQ / PR

Cos P = QR / PR

=> SinP.CosP = (PQ . QR ) / PR²

=> SinP.CosP = (5 . 10 ) / 125

=> SinP.CosP = 2/5

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