triangle the venter are (0,1) (0,5) and (0,0) then are of triangle is
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vertices of triangle are (0,1) ,(0,5),(0,0)
Area of triangle = 1/2 [ x1( y2-y3)+x2(y3-y1)+x3(y1-y2)]
= 1/2 [ 0(5-0)+0(0-1)+0(1-5)]
1/2( 0+0+0)
1/2 ×0=0
Answer : area of triangle is 0 sq units, stating that the above three points cannot be the vertices of the triangle.
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