Question

triangle xyz, the bisector XM of angle X
is perpendicular to side Yz. Prove that xy=xz​

Answer 1

ANSWER

Since, ∠YXM=∠MXZ

as, XM is angle bisector.

and ∠XDA=∠XDB (Right angles)

and DX is common side.

So, △DXA=△DXB (ASA criteria.)

Thus, ∠DAX=∠DBX

So, AX=BX (Sides opposite to equal angles are equal.)

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