Trignometry Challenge (15 points ) -
If , sinQ + cosQ=1
Then Prove , 2sinQ -cosQ =2
Answers
Answered by
2
sinQ+ cosQ=1
root2 {1/root2. sinQ+1/root2.cosQ}=1
root2 {cos45.sinQ +cosQ.sin45}=1
sin (Q+45)=1/root2
sin (Q+45)=sin45
solve by trigeometric general solution.
Q+pi/4=n.pi +(-1)^n (pi/4)
put n=0
Q+ pi/4=0 +pi/4 , Q=0,
put n=1
Q+ pi/4=pi -pi/4
Q=pi/2
=========
=======
here we see Q=0, pi/2 ......
but condition
here proving 2sinQ-cosQ=2
so,
we only use Q=pi/2 not Q=0
now 2sinQ-cosQ=2 only when Q=pi/2
root2 {1/root2. sinQ+1/root2.cosQ}=1
root2 {cos45.sinQ +cosQ.sin45}=1
sin (Q+45)=1/root2
sin (Q+45)=sin45
solve by trigeometric general solution.
Q+pi/4=n.pi +(-1)^n (pi/4)
put n=0
Q+ pi/4=0 +pi/4 , Q=0,
put n=1
Q+ pi/4=pi -pi/4
Q=pi/2
=========
=======
here we see Q=0, pi/2 ......
but condition
here proving 2sinQ-cosQ=2
so,
we only use Q=pi/2 not Q=0
now 2sinQ-cosQ=2 only when Q=pi/2
Answered by
0
Answer:
I don't know sorryyyyyyyy
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