Trignometry class 10
Question 9 and 10
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Sin a = 1- sin^2a
√(1-cos^2a) = cos^2a
1 - cos^2 a = cos^4 a
cos ^4 a + cos^2 a -1 = 0
cos^4 a+ Cos^2 a= 1
10)tan theta = 1/√3
theta = 30
cosec^2 30 - sec^2 30)/cosec^30+ sec^2 30
= 4 -4/3 ) /4+4/3
= 8/16 = 1/2
√(1-cos^2a) = cos^2a
1 - cos^2 a = cos^4 a
cos ^4 a + cos^2 a -1 = 0
cos^4 a+ Cos^2 a= 1
10)tan theta = 1/√3
theta = 30
cosec^2 30 - sec^2 30)/cosec^30+ sec^2 30
= 4 -4/3 ) /4+4/3
= 8/16 = 1/2
Simrancthakur:
Can u plz explain me the seconfd step
Hsjd
Khush
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