Math, asked by mnojkumarjha, 1 year ago

Trigonometric equation.....

general solution for

 \cos^{2} \alpha = \cos^{2} \beta \\ \\ \sin^{2} \alpha = \sin^{2} \beta \\ \\ \tan^{2} \alpha = \tan^{2} \beta

Answers

Answered by aman190k
2

The general solution for
Trigonometric equation.....

 \cos^{2} \alpha = \cos^{2} \beta \\ \\ \\ \alpha = n\pi +- \beta \\ \sin^{2} \alpha = \sin^{2} \beta \\ \\ \alpha = n\pi +- \beta \\ \\ \tan^{2} \alpha = \tan^{2} \beta \\ \\ \alpha = n\pi +- \beta

Similar questions