Math, asked by Brainly1119, 1 year ago

trigonometric identities

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Answered by utkbkkh
3
LHS=sin thita - cos thita + 1/ sin thita + cos thita - 1
Now, RHS=
1/sec thita - tan thita
=1/1/cos thita - 1/sin thita/ cos thita
=sin thita - cos thita +1/ sin thita + cos thita - 1
=LHS
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