Math, asked by DevilR6275, 11 months ago

Trigonometric identity of tan theta and sec theta

Answers

Answered by Kleela97

This is the identity ................

Attachments:

Answered by AkshatZayn

Trigonometric Ratios of tan∅ and sec∅

$<head><style type="text/css">.table th{ font-size: 12px;text-align: center;padding: 5px 10px;}.table td{ font-size: 10px;text-align: center;padding: 12px 5px;font-family: Times New Roman;}</style></head><body><table class="table" border="1px" cellspacing="0px"><tr><th bgcolor="#ccc"> ‹A </th><th bgcolor="#ccc"> 0°</th><th bgcolor="#ccc"> 30°</th><th bgcolor="#ccc">45° </th><th bgcolor="#ccc">60° </th><th bgcolor="#ccc"> 90° </th></tr><tr><td bgcolor="#ccc"> sec∅</td><td> 1 </td><td> 2/√3</td><td> √2</td><td> 2</td><td> Not defined</td></tr><tr><td bgcolor="#ccc"> tan∅</td><td> 0 </td><td> 1/√3</td><td> 1 </td><td> √3</td><td> Not defined</td></tr></table></body>$

Trigonometric Identities of tan∅ & sec∅

$\rm\fbox{1 + tan^2A = sec^2A}$

Previous Question

Next Question