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Trigonometry All formulas For IIT JEE

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Answered by hariharan108
2

Answer:

hope it is helpful and good luck

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Answered by Brenquoler
2

 { \red{ \bf{   Information \: related \: to \:Trigonometry:}}}

 { \green{ \bf{ sin θ = Opposite Side/Hypotenuse  }}}

 { \green{ \bf{  cos θ = Adjacent Side/Hypotenuse }}}

 { \green{ \bf{tan θ = Opposite Side/Adjacent Side   }}}

 { \green{ \bf{sec θ = Hypotenuse/Adjacent Side   }}}

 { \green{ \bf{  cosec θ = Hypotenuse/Opposite Side }}}

 { \green{ \bf{  cot θ = Adjacent Side/Opposite Side }}}

 { \red{ \bf{Their \: reciprocal \: Identities:   }}}

 { \green{ \bf{  cosec θ = 1/sin θ }}}

 { \green{ \bf{ sec θ = 1/cos θ  }}}

 { \green{ \bf{  cot θ = 1/tan θ }}}

 { \green{ \bf{sin θ = 1/cosec θ   }}}

 { \green{ \bf{ cos θ = 1/sec θ  }}}

 { \green{ \bf{   tan θ = 1/cot θ}}}

 { \red{ \bf{ Their \: co-function \: Identities:  }}}

 { \green{ \bf{  sin (90°−x) = cos x }}}

 { \green{ \bf{cos (90°−x) = sin x   }}}

 { \green{ \bf{ tan (90°−x) = cot x  }}}

 { \green{ \bf{  cot (90°−x) = tan x }}}

 { \green{ \bf{ sec (90°−x) = cosec x  }}}

 { \green{ \bf{ cosec (90°−x) = sec x  }}}

 { \red{ \bf{ Their \: fundamental \: trigonometric \: identities:  }}}

 { \green{ \bf{  sin²θ + cos²θ = 1 }}}

 { \green{ \bf{  sec²θ - tan²θ = 1 }}}

 { \green{ \bf{ cosec²θ - cot²θ = 1  }}}

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