(Trigonometry CBSE Class X) Please solve 22 and 23..With an explanation please.
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hope it helped u bro
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KarthikHariiii:
ill tell how to solve qn 23
sec2 is 1/cos2....so u have to solve (1/cos2)-sin2
by taking lcm ull get 1-(sin2cos2)/cos2
now solve using denominator
(1-(sin2cos2)/cos2)÷(sin2/cos2)
by taking reciprocal(because both numerator nd denominator js in fraction
Ok..Thanks man!
ull get 1-sin2cos2/sin2
split em up
ull get
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