Question

trigonometry chapter 11th​

Answer 1

Answer:

as we know that, (sina+sinb=2sin(a+b2)cos(a−b2))

so, 2sin4x.cos(−2x)−sin4x=0

=sin4x(2cos2x−1)=0

now it can possible that whether sin4x=0or2cos2x−1=0

when sin4x=0

4x=nπ&n∈z

x=nπ4

when 2cos2x−1=0

cos2x=cos(π3)

2x=2nπ±π3

x=nπ±π6

answer =  nπ4,nπ±π6

Answer 2

Step-by-step explanation:

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Don't touch your face again and again.

Wash hair regularly and keep them away from the face.

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