Question

Trigonometry class 10th


$\huge\left. \begin{array} { l } { \frac { 1 - \sin \theta } { \cos \theta } = \frac { \cos \theta } { 1 + \sin \theta } } \end{array} \right.$

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Answer 1

Step-by-step explanation:

$\frac{1 - \sin(a) }{ \cos(a) } = \frac{ \cos(a) }{1 + \sin(a) } \\ \\ = (1 - \sin(a) )(1 + \sin(a) ) \\ \\ \ = \cos(a) \times \cos(a) \\ \\ ({1 - \sin(a) })^{2} = ({ \cos(a) })^{2} \\ \\ we \: know \: that \: ( {1 - \sin(a) }) ^{2} = \ { \cos(a) }^{2} \\ \\ { \cos( a ) }^{2} = { \cos(a) }^{2}$ Mark me as brainliest

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